Hello,
I want to compile a LLVM file into an executable running on ARM platform.
I use LLVM 2.0 with the following command lines:
llvm-as -f –o test.bc test.ll
llc –march=arm –mcpu=arm1136j-s –mattr=+v6 –f –o test.s test.bc
arm-linux-gnu-as –mcpu=arm1136j-s test.s
With the last command, I obtain the following error:
rd and rm should be different in mul
The bad instruction is “mul r3, r3, r2” that follows the syntax “mul rd, rm, rs”.
I want to know where is my mistake or if it is a bug in register allocator ?
Thanks in advance.
Mikaël.
target datalayout = “e-p:32:32:32-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:32:64-f32:32:32-f64:32:64-v64:64:64-v128:128:128-a0:0:64”
@.str1 = internal constant [4 x i8] c"%d\0A\00"
declare i32 @printf(i8*, …)
define i32 @main (){
entry:
%n = alloca i32
%f = alloca i32
%i = alloca i32
%zero = alloca i32
%inc = alloca i32
store i32 5, i32* %n
store i32 1, i32* %f
store i32 1, i32* %i
store i32 0 , i32* %zero
store i32 1 , i32* %inc
%tmp7 = load i32* %n
%tmp8 = load i32* %zero
%tmp6 = icmp sgt i32 %tmp7, %tmp8
br i1 %tmp6, label %then4, label %else12
then4:
%tmp14 = load i32* %i
%tmp16 = load i32* %n
%tmp18 = load i32* %inc
%tmp15 = add i32 %tmp16, %tmp18
%tmp13 = icmp slt i32 %tmp14, %tmp15
br i1 %tmp13, label %then11, label %else12
then11:
%tmp20 = load i32* %f
%tmp22 = alloca i32
store i32 1 , i32* %tmp22
%tmp23 = load i32* %tmp22
%tmp24 = load i32* %i
%tmp21 = add i32 %tmp24, %tmp23
store i32 %tmp21, i32* %i
%tmp19 = mul i32 %tmp20, %tmp21
store i32 %tmp19, i32* %f
br label %then4
else12:
%tmp25 = load i32* %f
%tmp335 = getelementptr [4 x i8]* @.str1, i32 0, i32 0
%tmp336 = call i32 (i8*, …)* @printf( i8* %tmp335, i32 %tmp25 )
ret i32 %tmp25
}