Hi All,
I am trying to check if a Value type is a int32 pointer by using
if(T == Type::getInt1PtrTy(Context, AS)) …
I am trying to understand the AS (address space).
How do I get it? Thanks.
George
Hi,
You don't need to care about address spaces to check for an int32*:
if (T->isPointerTy()) {
const Type* intT = cast<PointerType>(T)->getElementType();
if (intT->isIntegerTy() && intT->getPrimitiveSizeInBits() == 32)
cout << "Yeah!" << endl;
}
Also, to create a pointer type, if you don't care about address space
at all, use the unqualified version:
const Type* ptrT = PointerType::getUnqual(intT);
cheers,
--renato
The more idiomatic way would be:
if (const PointerType *Ptr = dyn_cast<PointerType>(T))
if (Ptr->getElementType()->isIntegerTy(32))
cout << "Yeah!" << endl;
John.
Nice! I was stuck with get-size-in-bits for years and never bothered
to look for an alternative, thanks! 
cheers,
--renato