FW: question about malloc call vs. instruction

I'm forwarding this question to llvmdev:

printing out a bunch of instructions. which reveals my new problem: when
i attempt a malloc in my own, it comes out like this:

%reg216 = call int (...)* %malloc( ulong 8 ) ; <int> [#uses=1]
a call to malloc, not a malloc instruction. i don't know how to get the
information i need out of a call to malloc.

You need to #include <stdlib.h>. Try compiling with warnings on (-Wall
-W), and you should get diagnostics for problems like this.

when i replace 'malloc' in the code with 'alloca', i get
%reg107 = alloca ubyte, uint 8 ; <ubyte*> [#uses=1]
so everything is fine for alloca.

alloca doesn't require a prototype.

i thought if i ran the inline pass it might change a malloc call to a
malloc instruction, but it didn't. can you tell me what's up here?

No prototype = Not a known function... The inlining pass shouldn't touch
malloc instructions/calls. The malloc calls should be eliminated by a
pass "built into" the GCC frontend:


... but this only will work if there is a prototype for the function.