A function declaration declares a function pointer to the memory where the machine code will be at runtime. Besides providing the ability to call the function, that pointer can also be used, after bitcasting it, to modify the machine code implementing the function. What does the optimizer assume about the memory containing the machine code?
The following is an example where Alive2 assumes that transforming @src to @tgt is correct (note that @f is marked readnone):
declare i32 @f() readnone
declare void @modify_f()
define i32 @src() {
call void @modify_f()
%r = call i32 @f()
ret i32 %r
}
define i32 @tgt() {
%r = call i32 @f()
call void @modify_f()
ret i32 %r
}
Is this actually a correct transformation?
If yes, what is the exact rule?
Several possibilities come to my mind:
* The memory at @f is assumed to be constant. If this is the case, how can it be communicated to the optimizer that the memory is modified?
* In the following part of the definition of the "readnone" attribute, "memory" includes the machine code of the callee: "On a function, this attribute indicates that the function computes its result (or decides to unwind an exception) based strictly on its arguments, without dereferencing any pointer arguments or otherwise accessing any mutable state (e.g. memory, control registers, etc) visible to caller functions.". However, then the following part would be inconsistent (if executing machine code is considered reading): "If a readnone function reads or writes memory visible to the program, or has other side-effects, the behavior is undefined.".