Building a new struct type, etc

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1

Hi folks,

I was just wondering if someone would be willing to tell me the best way
to make a new structure type in LLVM and get it inserted as a valid type
into a particular Module instance?

I've done the following:

        vector<const Type*> types;
        types.push_back(Type::UIntTy);
        types.push_back(Type::UIntTy);
        structType = StructType::get(types);

But can't seem to find any member functions in Module that allow me to
introduce this as a new type...

Furthermore, how would I create a (preferably static) global instance of
the above structure type, together with a static initializer for it?

If there's some example code floating around somewhere for this, that'd
be sufficient; I simply couldn't find anything that did what I wanted.

Thanks in advance!

-j

2

I was just wondering if someone would be willing to tell me the best way
to make a new structure type in LLVM and get it inserted as a valid type
into a particular Module instance?

I know you've already figured out a solution, but here's an answer for
others who may be wondering the same:

I've done the following:
        vector<const Type*> types;
        types.push_back(Type::UIntTy);
        types.push_back(Type::UIntTy);
        structType = StructType::get(types);

But can't seem to find any member functions in Module that allow me to
introduce this as a new type...

Modules don't need to do anything special to use types: types are global
things which do not belong to a particular module. If you want to insert
a name into a particular module for a type (creating a '%foo = type {
uint,uint}' declaration in the llvm assembly), use the Module::addTypeName
method.

Furthermore, how would I create a (preferably static) global instance of
the above structure type, together with a static initializer for it?

Do something like this:

#include "Support/VectorExtras.h"
static const Type *Ty = StructType::get(make_vector(Type::UIntTy,
                                                    Type::UIntTy, 0));

-Chris