Hi LLVM-dev!
I'm having problems figuring out how to do variable sized structs in LLVM (which are neccessary for PyPy's LLVM backend, on which I'm working). I'm trying to do the equivalent of
struct array {
long refcount;
long length;
long items[1];
};
in LLVM, where the items array can be arbitrarily long. I guess that the struct definition should be something like:
%array = type {int, int, [1 x int]}
but how would I allocate such a thing, with the items array being, say, 9 items long? In C I would do something like:
malloc(sizeof(struct array) + ((9 - 1) * sizeof(long)));
but there is no sizeof in LLVM, right? If I try compile C code like that with the LLVM C frontend, I get
%struct.array = type { int, int, [1 x int] }
...
%tmp.0 = malloc [44 x sbyte]
%tmp.5 = cast [44 x sbyte]* %tmp.0 to %struct.array*
It is clear what happens here, but I don't know how I would reproduce that, because I can't easily find out the length in bytes of the array.
I can think of workarounds (like using the struct module of the Python standard library to calculate the sizes) but I have the feeling that I'm missing something and there is a simple way to do that in LLVM.
Thanks for any help,
Carl Friedrich
One of LLVM's powerful (IMHO) selling points was the